Two customers Shyam and Ekta are visiting a particular shop in the same weak (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on (i) the same day? (ii) consecutive days? (iii) different days?

Solution

Total possible ways of visiting shop by them = 5 x 5 = 25
(i) They can visit the shop on a 11 week days Tuesday to Saturday.
Let A be the favourable outcomes of visiting shop by them on the same day = 5 Then, n(A) = 5

Therefore. P(A)=

fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 5 over 25 equals 1 fifth

(ii) Let Be be the favourable outcomes of visiting shop on the different days by them = 25 – 5 = 20 days.
i.e. n(B) = 20
Therefore, P(B) = $fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 20 over 25 equals 4 over 5$
(iii) Shyam T W Th. F
Ekta W Th. F S

Ekta T W Th. F
Shyam W Th. F S

Let A be the favourable outcomes of visiting shop on consecutive days.

Then, n(A) = 8
Therefore, P(A) = $fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 8 over 25$ .

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Real Numbers

Two customers Shyam and Ekta are visiting a particular shop in the same weak (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on (i) the same day? (ii) consecutive days? (iii) different days?

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The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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