Real Numbers

Question

Out of 400 bulbs in a box, 15 bulbs are defective. One bulb is taken out at random from the box. Find the probability that the drawn bulb is not defective.

Solution

TotaLnumbers of bulbs = 400 i.e. n{S) = 400
Let A be the favourable outcomes of getting 'non defective bulb', then
n(A) = 385
Therefore,
$straight P left parenthesis straight A right parenthesis equals fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 385 over 400 equals 77 over 80.$

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Real Numbers

Out of 400 bulbs in a box, 15 bulbs are defective. One bulb is taken out at random from the box. Find the probability that the drawn bulb is not defective.

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