A box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is
(a) White (b) neither red nor white

Solution

Number of red balls in the box = 5
Number of green balls in the box = 4
Number of white balls in the box = 7
Total number of balls in the box = 16
i.e., n (S) = 16
(i) Let A be the favourable outcomes of getting white balls, then
n(A) = 7
Therefore,
P(A) = $fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 7 over 16$
(ii) Let B be the favourable outcomes of getting neither red nor white balls, then
n(B) = 1 - P (red or white)
= 1 - [P (red) + P (white)]
$equals space 1 space minus open square brackets 5 over 16 plus 7 over 16 close square brackets equals space 1 minus 12 over 16 equals 4 over 16 equals 1 fourth$

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Real Numbers

A box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is
(a) White (b) neither red nor white

Some More Questions From Real Numbers Chapter

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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NCERT Sample Papers

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For Daily Free Study Material Join wiredfaculty

Real Numbers

A box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is(a) White (b) neither red nor white

Some More Questions From Real Numbers Chapter

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is
(a) White (b) neither red nor white