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Real Numbers

Question
CBSEENMA10009392

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is four times that of a red ball. Find the number of blue balls in the bag.

Solution

Number of red balls in the bag = 5
Let number of blue balls in the bag = x
Now, total number of balls in the bag = x + 5
i.e.,    n( S) = n + 5
(i) Let ‘A’ be the favourable outcomes of getting blue balls, then
n( A) = x
Therefore,
P(A) = fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals fraction numerator x over denominator x plus 5 end fraction

(i) Let 'B' be the favourable outcomes of getting red balls, then
n(B) = 5
Therefore,
P(B) = fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals fraction numerator x over denominator x plus 5 end fraction
According to question :
    P(A) = 4 P (B)
rightwards double arrow space space space space fraction numerator straight x over denominator straight x plus 5 end fraction equals 4 open parentheses fraction numerator 5 over denominator straight x plus 5 end fraction close parentheses
rightwards double arrow space space straight x space equals space 20
Hencem the number of blue balls in the bag is 20.