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Real Numbers

Question
CBSEENMA10009390

A bag contains 4 red, 5 black and 3 yellow balls. A ball is taken out of the bag at random. Find the probability that the ball taken out is of (i) yellow colour (ii) not of red colour.

Solution

No. of red balls    = 4
No. black balls    = 4
No. of yellow balls    = 3
Total no. of balls (4+5+3) = 12 n(S) = 12
I. Let ‘A’ be the favourable outcomes of getting the ball taken out is of ‘yellow colour’ 1 hen
n( A) = 3
Therefore,
rightwards double arrow space space space space space space straight P left parenthesis straight A right parenthesis space equals space fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 3 over 12 equals 1 fourth

II. Let ‘B’ be the favourable outcomes of getting the ball taken out is of ‘not of red colour’ I hen,
i.e.,    n(B) = 8
Therefore,
rightwards double arrow space space space space straight P left parenthesis straight B right parenthesis space equals space fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 8 over 12 equals 2 over 3