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Real Numbers

Question
CBSEENMA10009388

All cards of ace, jack and queen are removed from a deck of playing cards. One card is drawn at random from the remaining cards, find the probability that the card drawn is

(a)    a face card
(b)    not a face card

Solution

Out of 52 cards all cards of ace, jack and queen are removed.
So, remaining cards = 52 – 12 = 40 i.e., n(S) = 40
(a) Let E be the favourable outcomes of getting face cards, then
E= {total face cards - face cards which are removed}
E = {12-8} i.e.,    n(E) = 4
Now, P (getting face cards)
equals space fraction numerator straight n left parenthesis straight E right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 4 over 40 equals 1 over 10

(b) Let 'F' be the favourable outcomes of getting 'not a face card', then
F = {40 – 4} i.e.,    n( F) = 36
Now, P (getting not a face card)
equals space fraction numerator straight n left parenthesis straight E right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 36 over 40 equals 9 over 10

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