A pair of dice is thrown once. Find the probability of getting the same number on each dice.

Solution

When a pair of dice is thrown once then possible outcome(s) are 36. i.e.,    n( S) = 36
Let A be the favourable outcomes of getting the same number of each dice, then
S= ((1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2.1),    (2,2), (2,3), (2,4), (2,5), (2,6)
(3.1),    (3,2), (3,3), (3,4), (3,5), (3,6)
(4.1),    (4,2), (4,3), (4,4), (4,5), (4,6)
(5.1),    (5,2), (5,3), (5,4), (5,5), (5,6)
(6.1),    (6,2), (6,3), (6,4), (6,5), (6,6)}
⇒ (A) = {(11), (2,2), (3,3), (4,4), (5,5), (6,6))
i.e. n( A)= 6
Therefore,
$rightwards double arrow space space space space P left parenthesis A right parenthesis equals fraction numerator n left parenthesis A right parenthesis over denominator n left parenthesis S right parenthesis end fraction equals 6 over 36 equals 1 over 6$

For Daily Free Study Material Join wiredfaculty

Real Numbers

A pair of dice is thrown once. Find the probability of getting the same number on each dice.

Some More Questions From Real Numbers Chapter

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Location