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Real Numbers

Question
CBSEENMA10009372

A pair of dice is thrown once. Find the probability of getting a total of 5 on two dice.

Solution

If a pair of dice is thrown once, then possible outcomes(s) are 36. i.e.,    n(S) = 36
Let E be the favourable outcomes of getting a total of 5 on two dice, then
E = {(1, 4), (2, 3), (3, 2), (4,1)}
⇒    n(E) = 4
Therefore,   P(E) = fraction numerator straight N left parenthesis straight E right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 4 over 36 equals 1 over 9