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Real Numbers

Question
CBSEENMA10009371
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Two dice are thrown simultaneously. Find the probability that the sum of the two numbers appearing on the top is less than or equal to 10.

Solution

Let A be the favourable outcomes of getting the sum of the two numbers appearing on the top is less than or equal to 10, then

A = (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2.1),    (2,2), (2,3), (2,4), (2,5), (2,6)

(3.1),    (3,2), (3,3), (3,4), (3,5), (3,6)

(4.1),    (4,2), (4,3), (4,4), (4,5), (4,6)

(5.1),    (5,2), (5,3), (5,4), (5,5)

(6.1),    (6,2), (6,3)/ (6,4) i.e., n( A) = 33

Therefore,  
rightwards double arrow space space space space space space space space straight P left parenthesis straight A right parenthesis space equals space fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 33 over 36 equals 11 over 12

Some More Questions From Real Numbers Chapter

The probability of an event that cannot happen is ________ Such an event is called __________.

The probability of an event that is certain to happen is ________ Such an event is called _________.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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