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Real Numbers

Question
CBSEENMA10009370
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A die is thrown once. Find the probability of getting
(i)    a prime number
(ii)    a number divisible by 2

Solution

(i) If a die is thrown once, then possible outcomes are

S {1, 2, 3, 4, 5, 6} i.e. n(S) = 6 Let A be the favourable outcomes of setting a prime number, than A = {2, 3, 5} i.e. n(A) = 3 Therefore,
P(A) = fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 3 over 6 equals 1 half
(ii) Let B be the favourbale outcomes of setting a number divisibel by 2, then B = {2, 4, 6} i.e. n(B) - 3
Therefore, P(B) = fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 3 over 6 equals 1 half

Some More Questions From Real Numbers Chapter

Probability of an event E + Probability of the event ‘not E’_______.

The probability of an event that cannot happen is ________ Such an event is called __________.

The probability of an event that is certain to happen is ________ Such an event is called _________.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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