Real Numbers

Question

A die is rolled once, find the probability of getting a number greater than 2.

Solution

If we roll a die once, then possible outcomes (s), are
S = (1, 2, 3, 4, 5, 6)
⇒ n( S) = 6
Let E be the favourable outcomes of getting a number greater than 2, then E = { 3, 4, 5, 6, }
⇒ n(E) = 4
Therefore, P(E) = $fraction numerator straight n left parenthesis straight E right parenthesis over denominator nm left parenthesis straight S right parenthesis end fraction equals 4 over 6 equals 2 over 3$

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Real Numbers

A die is rolled once, find the probability of getting a number greater than 2.

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