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Real Numbers

Question
CBSEENMA10009362
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Two coins are tossed simultaneously. Find the probability of getting.
(i) two heads, (ii) at least one head, (iii) no head.

Solution

If we toss two coins simultaneously, then possible out comes (s), are
S = { HT, TH, HH, TT }
⇒    n( S) = 4
Let E be the favourable outcomes of getting two heads, then
E = { H H }
⇒    n(E) = 1
Therefore,   P(E) = fraction numerator straight n left parenthesis straight E right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 1 fourth

Let F be the favourable outcomes of getting at least one head, then
F = { HH, HT, TH }
⇒    n(F) = 3
Therefore,   P(F) = fraction numerator straight n left parenthesis straight F right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 3 over 4

Let G be the favourable outcomes of getting no head then
⇒    n (G) = 1
Therefore,   P(G) = fraction numerator straight n left parenthesis straight G right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 1 fourth.

Some More Questions From Real Numbers Chapter

The probability of an event that is certain to happen is ________ Such an event is called _________.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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