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Real Numbers

Question
CBSEENMA10009361
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A pair of coin is thrown once. Find the probability of (i) One Head, (ii) Two Tails.

Solution

If we toss a pair of coins twice then we get following possible outcomes (S).
i.e.,    S = { HT, TH, HH, TT }
⇒    n(S) = 04
Let E be the favourable outcomes of getting one head, then
E = { HT, TH }
⇒    n(E) = 2
Therefore,  P(E) = fraction numerator straight n left parenthesis straight E right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 2 over 4 equals 1 half

Let F is the favourable outcomes of getting two tails, then
F = { T, T }
⇒    n(F) = 1
Therefore,    P(F) = fraction numerator straight n left parenthesis straight F right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 1 fourth.

Some More Questions From Real Numbers Chapter

The probability of an event that cannot happen is ________ Such an event is called __________.

The probability of an event that is certain to happen is ________ Such an event is called _________.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

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