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Real Numbers

Question
CBSEENMA10009342

A die thrown once. Find the probability of getting
(i)    an even prime number
(ii)    a multiple of 3

Solution

If a die thrown once then possible outcomes are
S = {1, 2, 3, 4, 5, 6} i.e. n(S) = 6
(i) Let A be the favourable outcomes of getting an even prime number, then
A = [2] i.e. n(A) = 2
Therefore, P(A) = fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 1 over 6

(ii) Let B be the favourable outcomes of getting a multiple of three, then
B = {3,6} i.e. n(B) = 2
Therefore, P(B) = fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 2 over 6 equals 1 third