Question

A die is thrown once. Find the probablity of setting ‘a’ prime number.

Solution

If a die is thrown once, then
S = {1,2,3,4,5,6} i.e. n(s) = 6
Let A be favourable outcomes of setting a prime number, then
A = {2,3,5} i.e. n(4) = 3
Therefore, P(A) = $fraction numerator n left parenthesis A right parenthesis over denominator n left parenthesis S right parenthesis end fraction equals 3 over 6 equals 1 half$

Some More Questions From Real Numbers Chapter

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Real Numbers

A die is thrown once. Find the probablity of setting ‘a’ prime number.

Some More Questions From Real Numbers Chapter

Probability of an event E + Probability of the event ‘not E’_______.

The probability of an event that cannot happen is Such an event is called __.

The probability of an event that is certain to happen is Such an event is called _.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

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Email Address

Location

For Daily Free Study Material Join wiredfaculty

Real Numbers

A die is thrown once. Find the probablity of setting ‘a’ prime number.

Some More Questions From Real Numbers Chapter

Probability of an event E + Probability of the event ‘not E’_______.

The probability of an event that cannot happen is ________ Such an event is called __________.

The probability of an event that is certain to happen is ________ Such an event is called _________.

The sum of the probabilities of all the elemen-tary events of an experiment is ______.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The probability of an event that cannot happen is Such an event is called __.

The probability of an event that is certain to happen is Such an event is called _.