-->

Probability

Question
CBSEENMA10009103

The table below shows the daily expenditure on food of 25 household in a locality.

Daily Exp. (in Rs.)

100-150

150-200

200-250

250-300

300-350

No. of house hold

4

5

12

2

2

Find the mean daily expenditure on food by a suitable method.

Solution

Here.
We have                        sum from blank to blank of f subscript i equals 25 comma space space space sum from blank to blank of f subscript i u subscript i equals negative 7 comma space   A (assumed mean) = 225 and h = 50
Now,                              top enclose straight x equals space A plus fraction numerator begin display style sum from blank to blank of end style f subscript i u subscript i over denominator begin display style sum from blank to blank of end style f subscript i end fraction x h equals 225 plus fraction numerator negative 7 over denominator 25 end fraction x 50 equals 225 minus 14 equals 211
Hence, the mean daily expenses is 211.

Some More Questions From Probability Chapter