Water in a canal 30 dm wide and 12 dm deep, is flowing velocity of 10 km/hr. How much area will it irrigate if 8 cm of standing water is required for irrigation?

Solution

We have,
Width of the canal = 30 dm = 300 cm = 3 m
Depth of the canal = 12 dm = 120 cm = 1.2 m
It is given that the water is flowing with velocity 10 km/hr. Therefore length of the water column formed in $bold 1 over bold 2$ hour = 5 km = 5000 m
∵ Volume of the water flowing in $bold 1 over bold 2$ hour

= Volume of the cuboid of length = 5000 m,
Width = 3 m and depth = 1.2 m
= 5000 x 3 x 1.2 m³ = 18000 m³.
Suppose xm² area is irrigated in $1 half$ hour. Then,
$straight x cross times 8 over 100 equals 18000 rightwards double arrow space space straight x space equals space 1800000 over 8 straight m squared rightwards double arrow space space straight x space equals space 225000 space straight m squared$
Hence, the canal irrigates 22500 m² area in $bold 1 over bold 2$ hour.

For Daily Free Study Material Join wiredfaculty

Statistics

Water in a canal 30 dm wide and 12 dm deep, is flowing velocity of 10 km/hr. How much area will it irrigate if 8 cm of standing water is required for irrigation?

Some More Questions From Statistics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Location