Question
From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2.
Solution
Let r cm be the radius and h cm be the height of the cylinder, then
r = 0.7 cm and h = 2.4 cm.
Let r1 cm be the radius, l cm be the slant height and h1 cm be the height of the cone, then
r1 = 0.7 cm and h1 = 2.4 cm
Now,
Total surface area of the remaining solid
= (C.S.A of cylinder) + (C.S.A of cone) + (area of upper base of the cylinder)
= 2 π rh + πr2l + πr2
= 2 π rh + π rl + π r2 [ ∵ r = r1]