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Statistics

Question
CBSEENMA10008811

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 500 per m2. (Note that the base of the tent will not be covered with canvas.)

Solution

Let r m be the radius and l m be the slant height of the cone, then
r = 2 m, and l = 2.8 m
Let r1 m be the radius and h m be the height of the cylinder, then
Now, r1 – 2 m and h = 2.1 m
Area of the canvas used
= CSA of cone + CSA of cylinder
= πrl + 2 πr1h
= πrl + 2πrh [r = r1]
= π r (l + 2h) m
equals space open square brackets 22 over 7 space straight x space 2 space open curly brackets 2.8 space plus space 2 space left parenthesis 2.1 right parenthesis close curly brackets close square brackets space straight m squared
equals space open square brackets 44 over 7 left parenthesis 2.8 plus 4.2 close square brackets space straight m squared
equals space open parentheses 44 over 7 space straight x space 7 close parentheses space straight m squared
equals space 44 space cm squared

and Cost of canvas of the tent
= Rs. (500 x 44)
= Rs. 22,000.

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