Sponsor Area

Areas Related To Circles

Question
CBSEENMA10008572

Construct a ΔPBC, similar to a given ΔPQR, with QR = 6 cm, PR = PQ = 5 cm, such that each of its side is 5/7th of the corresponding sides of the ΔPQR.

Solution

Steps of Construction :

(i)    Construct a ΔPQR in which PR = PQ = 5 cm and QR = 6cm.
(ii)    At P draw an acute ∠QPX, below base PQ.
(iii)    Along PX, mark off
P1, P2, P3,..., P6,P7.
(iv)    Join P7Q.
(v)    From P5 draw P5B || P7Q meeting PQ at B.
(vi)    From B, draw BC || RQ meeting PR at C.
Thus ΔPBC is the required triangle, each of whose sides is 6 over 7 of the corresponding sides of the ΔPQR.