Sponsor Area

Areas Related To Circles

Question
CBSEENMA10008560

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 5 over 3 times the corresponding sides of the given triangle. 

Solution

Steps of Construction :
(i) Draw line BC = 4 cm.
(ii) Draw BA = 3 cm line segment with 90° at B.

(iii)    Join AC to form right ΔABC.
(iv)    Construct an acute ∠CBX downwards.
(v)    Along BX mark off 5 equal points B1, B2, B3, B4, B5 such that BB1 = B1B2=... = B4B5.
(vi)    Join C to B3 and draw a line through B5 parallel to B3C intersecting the extended line segment BC at C’.
(vii)    Again we draw C’A’ parallel to AC.Thus, ΔA‘BC’ is the required triangle.
Justification :