Sponsor Area

Areas Related To Circles

Question
CBSEENMA10008555

Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides arc 2 over 3 of the corresponding sides of the first triangle.

Solution
Steps of Construction :

(i) Construct a ΔABC in which AB = 6 cm, AC = 4 cm, BC = 5 cm.
(ii)    At A draw an acute ∠BAX below base AB.
(iii)    Along AX mark off points A1, A2, A3 such that AA1 = A1 A1 = A2 A3.
(iv)    Join A3B.
(v)    From A2 draw A2B’ || A3B meeting AB at B’.
(vi)    From B’ draw B‘C’ || CB meeting AC at C’. Thus, ΔAB‘C’ is the required triangle, each of whose sides is (2/3)rd of the corresponding sides of the ΔABC.
Justification :

[From (i)]
[By Basic proportionality theorem)