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Circles

Question
CBSEENMA10008337

Two ships are sailing in the sea on the either side of the lighthouse, the angles of depression of two ships as observed from the top of the lighthouse are 60° and 45° respectively. If the distance between the ships is 200 open parentheses fraction numerator square root of 3 plus 1 over denominator square root of 3 end fraction close parentheses straight m. Find the height of the lighthouse.

Solution
Let AD be the lighthouse of height h m B and C are the position of the two ships which are on the either side of the road. The angles of depression of the ships from the top of the light house be 60° and 45°, ie., ∠ABD = 60 and ∠ACD = 45°

Let BD = x m and CD = y m.
In right triangle ABD, we have
tan space 60 degree space equals space AD over BD
rightwards double arrow space space space square root of 3 equals straight h over straight x
rightwards double arrow space space space space straight x space equals space fraction numerator straight h over denominator square root of 3 end fraction space space space space space space space space space space space... left parenthesis straight i right parenthesis
In right triangle ACD, we have
tan space 45 degree space space equals space AD over CD
rightwards double arrow space space space space space space space space space space space space space space 1 space equals space straight h over straight y
rightwards double arrow space space space space space space space space space space space space space space space straight y space equals space straight h space space space space space space space space space space space space space space... left parenthesis ii right parenthesis
Adding (i) and (ii), we get
straight x space plus space straight y space equals space fraction numerator straight h over denominator square root of 3 end fraction space plus space straight h
rightwards double arrow space space 200 open parentheses fraction numerator square root of 3 plus 1 over denominator square root of 3 end fraction close parentheses equals fraction numerator straight h plus square root of 3 straight h end root over denominator square root of 3 end fraction
rightwards double arrow space 200 space open parentheses fraction numerator square root of 3 plus 1 over denominator square root of 3 end fraction close parentheses equals fraction numerator straight h left parenthesis 1 plus square root of 3 right parenthesis over denominator square root of 3 end fraction
rightwards double arrow space space space space straight h space equals space 200
Hence, the height of the light house = 200 m.

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