Question
A ladder rests against a wall at an angle α to the horizontal, its foot is pulled away from the wall through a distance a, so that it slides a distance b down the wall making an angle β with the horizontal. Show that 
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Solution
Let BC be the ladder which slides down a distance b on the wall.
In right triangle ABC, we have
So, replacing AE by ED sin β, we get 
As, BC and ED both represent the same ladder.
BC = ED. (length of ladder does not change)
⇒ BC sin α - BC sin β = b
⇒ BC (sin α - sin β) = b ...(i)
Similarly, in right triangle AED, we have
So, by replacing AC by BC cos α, we get ED cos β = BC cos α + a BC (cos . - cos α) = a [∴ ED = BC] ...(ii) Dividing (ii) by (i), we get
