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Circles

Question
CBSEENMA10008328

If the angle of elevation of a cloud from a point h metres above a lake is α and the angle of depression of its reflection in the lake be β. Prove that the distance of the cloud from the point of observer is  fraction numerator 2 straight h space sec space straight alpha over denominator tan space straight beta space minus space tan space straight alpha end fraction.

Solution

et AB be the surface of the lake and 'P' be the position of the observer h metres above the lake. Let C be the cloud and C' be the reflection in the cloud. Then CB = C'B. It is also given that the angle of elevation of cloud from a point h m above a lake is α and angle of depression of its reflection be β. i.e., ∠CPQ = α and ∠QPC' = β. Let CQ = xm.
In right triangle PQC, we have

In right triangle PQC, we have
sin space straight alpha space equals space CQ over CP
rightwards double arrow space sin space straight alpha space equals space straight x over CP
rightwards double arrow space space space space straight x space equals space CP space sin space straight alpha space space space space space space space space space space space... left parenthesis straight i right parenthesis
and space space space tan space straight alpha space space equals space CP over PQ
rightwards double arrow space space space tan space straight alpha space equals space straight x over PQ
rightwards double arrow space space space PQ space equals space fraction numerator straight x over denominator tan space straight alpha end fraction space space space space space space space space space space space... left parenthesis ii right parenthesis
In right triangle PQC', we have
tan space straight beta space space equals space fraction numerator QC apostrophe over denominator PQ end fraction
rightwards double arrow space space tan space straight beta space equals space fraction numerator BQ space plus space BC apostrophe over denominator PQ end fraction
rightwards double arrow space space tan space straight beta space equals space fraction numerator straight h plus straight x plus straight h over denominator PQ end fraction
rightwards double arrow space space space PQ space equals space fraction numerator 2 straight h plus straight x over denominator tanβ end fraction space space space space space space space space space space space space space space space... left parenthesis iii right parenthesis
Comparing (ii) and (iii), we get
fraction numerator straight x over denominator tan space straight alpha end fraction space equals space fraction numerator 2 straight h plus straight x over denominator tan space straight beta end fraction
straight x space tan space straight beta space equals space 2 straight h space tan space straight alpha space plus straight x space tan space straight alpha
rightwards double arrow space straight x space tan space straight beta space minus space straight x space tan space straight alpha space equals space 2 straight h space tan space straight alpha
rightwards double arrow space straight x left parenthesis tan space straight beta space minus space tan space straight alpha right parenthesis space equals space 2 straight h space tan space straight alpha
rightwards double arrow space straight x space equals space fraction numerator 2 straight h space tan space straight alpha over denominator tan space straight beta space minus space tan space straight alpha end fraction space space space space space space space space space space space space space space... left parenthesis iv right parenthesis
Comparing (i) and (iv), we get
CP space sin space straight alpha space equals space fraction numerator 2 straight h space tan space straight alpha over denominator tan space straight beta space minus space tan space straight alpha end fraction
CP space equals space fraction numerator 2 straight h space tan space straight alpha over denominator sin space straight a left parenthesis tan space straight beta space minus space tan space straight alpha right parenthesis end fraction
space space space space space equals space fraction numerator 2 straight h over denominator cos space straight alpha end fraction cross times fraction numerator sin space straight alpha over denominator sin space straight alpha end fraction cross times fraction numerator 1 over denominator left parenthesis tan space straight beta minus tan space straight alpha right parenthesis end fraction
space space space space space equals space fraction numerator 2 straight h space sin space straight alpha over denominator sin space straight alpha space cos space straight alpha end fraction cross times fraction numerator 1 over denominator tan space straight beta space minus space tan space straight alpha end fraction
space space space space space equals space space fraction numerator 2 straight h over denominator cos space straight alpha end fraction cross times fraction numerator 1 over denominator tan space straight beta minus tan space straight alpha end fraction
space space space space space equals space space fraction numerator 2 straight h space sec space straight alpha over denominator tan space straight beta space minus space tan space straight alpha end fraction
Hence, the distance of the cloud from the point of observer is fraction numerator 2 straight h space sec space straight alpha over denominator tan space straight beta space minus space tan space straight alpha end fraction.