Question
From the top of a building 60 m high the angles of depression of the top and the bottom of tower are observed to be 30° and 60°. Find the height of the tower.
Solution
Let AC be the tower and BE be the building. Let height of the tower be h m. It is given that the angles of depression of the top C and bottom A of the tower, observed from top of the building be 30° and 60° respectively.

In right triangle CDE, we have

In right triangle ABE, we have

Comparing (i) and (ii), we get

Hence, the height of the tower is 40 m.

In right triangle CDE, we have

In right triangle ABE, we have

Comparing (i) and (ii), we get

Hence, the height of the tower is 40 m.