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Circles

Question
CBSEENMA10008315

An aeroplane at an altitude of 200 metres observes the angles of depression of opposite points on the two banks of a river to be 45° and 60°. Find the width of the river.

Solution
Let the position of the aeroplane be A, B and C be two points on the two banks of a river such that the angles of depression at B and C are 45° and 60° respectively. Let BD = x m, y m andAD = 200 m.

In right triangle ABD, we have
tan space 45 degree space space equals space AD over BD
rightwards double arrow space space space space 1 space space equals space 200 over straight x
rightwards double arrow space space space space space straight x space equals space 200 space space straight m space space space space space space space space space space space space space space space space space space space space... left parenthesis straight i right parenthesis
In right triangle ACD, we have
tan space 60 degree space space equals space AD over CD
rightwards double arrow space space space square root of 3 space equals space 200 over straight y
rightwards double arrow space space space space straight y space equals space fraction numerator 200 over denominator square root of 3 end fraction space space space space space space space space space space space space space space space space space... left parenthesis ii right parenthesis
Adding (i) and (ii), we get
space space space space straight x plus straight y space equals space 200 space plus space fraction numerator 200 over denominator square root of 3 end fraction
rightwards double arrow space space space space BC space equals space fraction numerator 200 square root of 3 plus 200 over denominator square root of 3 end fraction space straight m
space space space space space space space space space space space space space space equals space fraction numerator 200 open parentheses square root of 3 plus 1 close parentheses over denominator square root of 3 end fraction space straight m
space space space space space space space space space space space space space space space space equals space 315.4 space straight m
Hence, the width of the river is 315.4 metres.

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