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Circles

Question
CBSEENMA10008300

A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground. The angle of elevation of the balloon from the eyes of the girl at any instant is 60°. After some time, the angle of elevation reduces to 30° (see Fig. 9.13). Find the distance travelled by the balloon during the interval.

Fig. 9.13.

Solution
In right triangle EAG, we have
tan space 60 degree space equals space EG over AG
rightwards double arrow space space square root of 3 space space equals space 87 over AG
rightwards double arrow space space AG space space equals space space fraction numerator 87 over denominator square root of 3 end fraction space straight m
space space space space space space space space space space space equals space space fraction numerator 87 over denominator square root of 3 end fraction straight x fraction numerator square root of 3 over denominator square root of 3 end fraction equals fraction numerator 87 square root of 3 over denominator 3 end fraction straight m
space space space space space space space space space space space equals space space fraction numerator 87 space straight x space 1.732 over denominator 3 end fraction space straight m space equals space 50.23 space metres
In right triangle FAC, we have
tan space 30 degree space space equals space FC over AC
rightwards double arrow space space fraction numerator 1 over denominator square root of 3 end fraction equals 87 over AC
rightwards double arrow space space space space AC space equals space 87 square root of 3 space straight m
rightwards double arrow space space space space AC space equals space left parenthesis 87 space straight x space 1.732 right parenthesis space metres
space space space space space space space space space space space space space space equals space 150.68 space straight m

⇒ Distance travelled by the balloon
EF = GC = AC - AG
= (150.68 - 50.23) m
= 100.45 metres.

 

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