The string of akite is 100 m long and its makes an angle of 60° with the horizontal. Find the height of the kite. Assume that there is no slackness in the string.

Solution

Lenght of string OA = 100 m.
Angle of elevation = 60°. Let the heigth of the kite be AB = h m.

In right triangle OBA, we have
$sin space 60 degree space equals space AB over OA rightwards double arrow space space space space fraction numerator square root of 3 over denominator 2 end fraction equals straight h over 100 rightwards double arrow space space space space straight h space equals space 50 square root of 3$
Thus, the height of the kite is $50 square root of 3 space straight m.$

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Circles

The string of akite is 100 m long and its makes an angle of 60° with the horizontal. Find the height of the kite. Assume that there is no slackness in the string.

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