From a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30°, Find the height of the tower.

Solution

Let O be a point be a point 20 m away from the tower AB = hm
In right triangle OBA, we have

$tan space 30 degree space equals space AB over OB rightwards double arrow space space fraction numerator 1 over denominator square root of 3 end fraction equals straight h over 20 rightwards double arrow space space space straight h space equals space fraction numerator 20 over denominator square root of 3 end fraction straight m$
thus, th height of the tower is $fraction numerator 20 over denominator square root of 3 end fraction straight m.$

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Circles

From a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30°, Find the height of the tower.

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