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Circles

Question
CBSEENMA10008350

The height of a tower is 10 m. Calculate the height of its shadow when Sun's altitude is 45°. 

Solution
In figure, AB is the tower and BC is the length of the shadow when the Sun's altitude is 45°, i.e. the angle of elevation of the top of the tower from the tip of the shadow is 45

In right ∆ABC, we have
tan space 45 degree space equals space AB over BC
rightwards double arrow space space space space 1 space equals space 10 over BC rightwards double arrow BC space equals space 10 space straight m.
Thus, the height of the shadow is 10 m.

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