Question
The horizontal distance between two towers is 140 m. The angles of depression of the first tower, when seen from the top of the second tower is 30°. If the height of the first tower is 60 m. Find the height of the second tower.
Solution
AD and BE are two towers. The angle of depression of 1st tower (AD), when seen from the top of 2nd tower (BE) is 30°.
i.e., ∠CDE = 30°.
It is given that
AD = 60 m
and AB = CD = 140 m.
Let height of 2nd tower BE be h metres.
In right triangle CDE, we have
Hence, the height of the second tower is 140.83 m.
