A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string.

Solution

Let BC be the horizontal ground, and let A be the position of the kite which is at a height of 60 m. i.e., AB = 60 m.
It is given that
∠ACB = 60°
Now, in right triangle ABC, we have
$sin space space 60 degree space space space equals space AB over AC rightwards double arrow space space space fraction numerator square root of 3 over denominator 2 end fraction space equals space 60 over AC rightwards double arrow space space space space AC space space space equals space fraction numerator 60 space straight X space 2 over denominator square root of 3 end fraction rightwards double arrow space space space space AC space space space equals space fraction numerator 120 over denominator square root of 3 end fraction space straight X space fraction numerator square root of 3 over denominator square root of 3 end fraction rightwards double arrow space space space space AC space space space equals space space 40 square root of 3 space space straight m$
Hence, the length of string is $40 square root of 3 space straight m.$

For Daily Free Study Material Join wiredfaculty

Circles

A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string.

Some More Questions From Circles Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction