A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° (see Fig. 9.11)

Fig. 9.11

Solution

Let AC be the rope whose length is 20 m, and AB be the vertical pole of height h m and the angle of elevation of A at point C on the ground is 30°.

Fig. 9.11
i.e., ∠ACB = 30°
In right triangle ABC, we have
$sin space 30 to the power of degree space equals space AB over AC rightwards double arrow space space space space 1 half space equals space straight h over 20 rightwards double arrow space space space space 2 straight h space equals space 20 rightwards double arrow space space space space space straight h space equals space 10 space straight m$
Hence, the height of the pole is 10 m.

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Circles

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° (see Fig. 9.11)

Fig. 9.11

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For Daily Free Study Material Join wiredfaculty

Circles

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° (see Fig. 9.11)Fig. 9.11

Some More Questions From Circles Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30° (see Fig. 9.11)

Fig. 9.11