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Some Applications Of Trigonometry

Question
CBSEENMA10008269

Prove the following identity:
left parenthesis 1 plus tanA. tanB right parenthesis squared plus left parenthesis tanA minus tanB right parenthesis squared space equals sec squared straight A. space sec squared straight B.






Solution

L.H.S 
 equals space left parenthesis 1 plus tanA. space tanB right parenthesis squared plus left parenthesis tanA minus tanB right parenthesis squared
equals space left parenthesis 1 plus tan squared straight A. space tan squared straight B space plus space 2 space tanA. space tanB space plus space tan squared straight A space plus space tan squared straight B space minus space 2 space tanA. space tanB right parenthesis
equals space 1 plus tan squared straight A plus tan squared straight B plus tan squared straight A. space tan squared straight B
equals space left parenthesis 1 plus tan squared straight A right parenthesis plus space tan squared straight B left parenthesis 1 plus tan squared straight A right parenthesis
equals space left parenthesis 1 plus tan squared straight B right parenthesis thin space left parenthesis 1 plus tan squared straight A right parenthesis
equals space sec squared straight B. space sec squared straight A
equals space straight R. straight H. straight S.
Hence, L.H.S. = R.H.S.