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Arithmetic Progressions

Question
CBSEENMA10008081

Tanvika purchases every year National Saving Certificates of value exceeding the last year purchases by Rs. 25. After 20 years, he find the total value of certificates purchased by him is Rs. 7250. Find the value of the certificates purchased.

(i) in the first year. (ii) in the 12th year.

Solution
Let the value of certificates purchased in the first year be Rs. ‘a’ and annual increase = Rs.25. Here, first term = a, d = 25, S20 = 7250.
We know that,
 straight S subscript straight n equals straight n over 2 left square bracket 2 straight a space plus left parenthesis straight n minus 1 right parenthesis straight d right square bracket
rightwards double arrow space straight S subscript 10 equals 20 over 2 left square bracket 2 straight a plus left parenthesis 20 minus 1 right parenthesis 25 right square bracket
rightwards double arrow space 7250 space equals space 10 space left parenthesis 2 straight a plus 19 cross times 25 right parenthesis

⇒ 7250 = 10 (2a + 475)
⇒ 725 = 2a + 475 ⇒ 2a = 250
⇒ a = 125
Hence, the value of certificates purchased in first year = Rs. 125.
Now, value of certificates purchased in 12th year.
a12 = a + (12 – 1 )d = 125 + (11) (25) = 125 + 275 = Rs. 400.