The 17th term of an A .P. exceeds its 10th term by 7. Find the common difference.
Let a be the first term and d be the common difference of the A .P.
According to given statement,
a17 = a10 +7
⇒ a + 16d = a + 9d + 7
⇒ 16d – 9d = 1
⇒ 7d = 7
⇒ d = 1.
Let a be the first term and d be the common difference of the A .P.
According to given statement,
a17 = a10 +7
⇒ a + 16d = a + 9d + 7
⇒ 16d – 9d = 1
⇒ 7d = 7
⇒ d = 1.
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = 4, d = – 3
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
– 1.2, – 3.2, – 5.2, – 7.2, . . .
Mock Test Series