We have, an = –62,
a = 10 and d = –3 Now an = a + (n – 1)d
⇒ –62 = 10 + (n – 1) (– 3)
⇒ – 62 = 10 – 3n +3
⇒ – 62 = 13 – 3n
⇒ –3n = –75
⇒ n = 25
Now middle term = a13 = a + 12d
= 10 + 12(– 3)
= 10 – 36 = – 26
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a – 10, d = 10
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = –2, d = 0
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = 4, d = – 3
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .
Mock Test Series
