Write the common difference of an A .P. whose nth term is 3n + 5.
We have, an = 3n + 5
a1 = 3(1) + 5 = 3 + 5 = 8
a2 = 3 (2) + 5 = 6 + 5 = 11
And, a3 = 3 (3) + 5 = 9 + 5 = 14
Now, common difference = a2 – a1 = 11 – 8 = 3.
We have, an = 3n + 5
a1 = 3(1) + 5 = 3 + 5 = 8
a2 = 3 (2) + 5 = 6 + 5 = 11
And, a3 = 3 (3) + 5 = 9 + 5 = 14
Now, common difference = a2 – a1 = 11 – 8 = 3.
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = 4, d = – 3
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
– 1.2, – 3.2, – 5.2, – 7.2, . . .
Mock Test Series