Which term of the AP : 121, 117, 113, . . ., is its first negative term? [Hint : Find n for an < 0]
he given A .P. is 121, 117, 113, ... Here, a = 121
d = 117 – 121 = –4 Let the nth term of the A.P. be the first negative term. Then,
Least integral value of n = 32. Hence, 32nd term of the given A .P. is the first negative term 9.
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
– 1.2, – 3.2, – 5.2, – 7.2, . . .
Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
–10, –6, –2, 2, ....
Mock Test Series
