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Arithmetic Progressions

Question
CBSEENMA10007896

In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students?

Solution

Three sections of class I will plant = 1 x 3 = 3
Three sections of class II will plant = 2 x 3 = 6
Three sections of class III will plant = 3 x 3 = 9 and so on.
Three sections of class XII will plant = 12 x 3 = 36
So, we get an A .P. 3, 6, 9, ..., 36.
Here,      a =  3
              d = 6 - 3 = 3
              a= 36
We know that,    a= a +(n -1) d
rightwards double arrow        36 = 3 + (n - 1)d
rightwards double arrow      36 = 3 + (n - 1) x 3
rightwards double arrow      36 - 3 = 3 x (n - 1)
rightwards double arrow      33 = 3 x (n - 1)
rightwards double arrow space space space straight n minus 1 equals 33 over 3 equals 11
rightwards double arrow space space space space straight n space equals space 11 plus 1 equals 12
Now comma space space space space straight S subscript straight n equals straight n over 2 left parenthesis straight a subscript 1 plus straight a subscript straight n right parenthesis
therefore space space space space space space space space space straight S subscript 12 space equals 12 over 2 left parenthesis 3 plus 36 right parenthesis
space space space space space space space space space space space space space space equals space 6 cross times 39 equals 234
Hence, the number of trees planted by the students = 234. Ans.