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Arithmetic Progressions

Question
CBSEENMA10007854

In an A.P. 
Given a = 8, an = 62, Sn = 210, find ‘n’ and ‘d’.



Solution

Here a = 8

straight a subscript straight n space equals space 62 end subscript
S= 210
We know that, a= a + (n - 1)d
rightwards double arrow   62 - 8 = (n - 1)d
rightwards double arrow   54 = (n -d)d                   ...(i)
And,  Sn over 2 '[ 2a - (n - 1) d
rightwards double arrow  210 = n over 2[ 2 x 8 + (n - 1) d]
rightwards double arrow  420 = n[16 +(n - 1)d] .......(ii)
From (i) and (ii), we get
420  = n[ 16 + 54]
rightwards double arrow   420  = 70n
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Putting this value of n in (i) we get
54 = (6 -1) x d
rightwards double arrow     5d = 54
rightwards double arrow     d = 54 over 5
Hence,  n = 6 and d = space space 54 over 5.