Question
If sin θ = 1/3, then find the value of (2 cot2θ+ 2).
Solution
2cot2 θ + 2 =2 (cosec2θ - 1) + 2
= 2 cosec2 θ -2 + 2
= 2 cosec2 θ
= 2 cosec2 θ -2 + 2
= 2 cosec2 θ
