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Arithmetic Progressions

Question
CBSEENMA10007826

 Find the sum of three numbers is an A .P. is 27 and their product is 405. The numbers are : (a) (3,9,15) (b) (15, 9, 3) (c) both (a) and (b) (d) (3, 9, 12)

Solution

Let the three numbers are a - d, a and a + d
space space space space space space space therefore (a - d) +a + (a + d) = 27 rightwards double arrow a = 9, Also, (a - d) (a) (a + d) = 405 
Ans (c)