Question
In ΔPQR, right angled at Q. PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
Solution
We have,
Let
PR + QR = 25 cm ..(i)
PR = x cm
QR = (25 - x) cm.
Using Pythagoras theorem, we have
PR2 = PQ2 + RQ2
⇒x2 = (5Y + (25 - x)2
x2 = 25 + 625 + x2 - 50x
⇒50x = 650
⇒x = 13 cm
Now,
PR = x = 13 cm QR = (25 - x) = 12 cm
and
PQ = 5 cm
Now,
PQ = 5 cm
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