Question
Given 15 cot A = 8, find sin A and sec A.
Solution
Let us draw a right triangle ABC, right angled at B.
It is given that:
15 cot A = 8


It is given that:
15 cot A = 8



Let
AB = 8K, BC = 15K
Using Pythagoras theorem, we have
AC2 = AB2 + BC2 = (8K)2 + (15K)2
= 64K2 + 225K2
= 289K2
So,
AC = 17K
Now,
AC = 17K