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Arithmetic Progressions

Question
CBSEENMA10007534

Find the number of terms in each of the following APs :

space space space 18 comma space 15 1 half comma space 13 comma space....... comma space minus 47

Solution
bold space bold space bold space bold 18 bold comma bold space bold 15 bold 1 over bold 2 bold comma bold space bold 13 bold comma bold space bold. bold. bold. bold. bold. bold. bold. bold comma bold space bold minus bold 47
Here,    a= 18
            straight d space equals space 15 1 half minus 18 equals 31 over 2 minus 18 equals negative 5 over 2
And,      a= -47
Let the number of terms be n.
Then,      a= -47
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#6 {main}</pre>  a + (n - 1)d = - 47rightwards double arrow space 18 plus left parenthesis straight n minus 1 right parenthesis open parentheses fraction numerator negative 5 over denominator 2 end fraction close parentheses equals negative 47
rightwards double arrow space space fraction numerator negative 5 over denominator 2 end fraction left parenthesis straight n minus 1 right parenthesis equals negative 47 minus 18
rightwards double arrow space space space space fraction numerator negative 5 over denominator 2 end fraction left parenthesis straight n minus 1 right parenthesis equals negative 65
rightwards double arrow space space space space space 5 over 2 left parenthesis straight n minus 1 right parenthesis space equals space 65
rightwards double arrow space space straight n minus 1 space equals space fraction numerator 65 cross times 2 over denominator 5 end fraction
rightwards double arrow space space straight n space minus space 11 space equals space 26
rightwards double arrow space space straight n space equals space 26 space plus space 1 space
rightwards double arrow space space straight n space equals space 27
Hence, the number of terms of the given A .P. is 27.