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Arithmetic Progressions

Question
CBSEENMA10007533

Find the number of terms in each of the following APs :
7, 13, 19, . . . , 205

Solution

7, 13, 19, . . . , 205
Here,      a = 7
              d = 13 - 7 = 6
And,        a= 205
Let the number of terms be n.
Then,    a= 205
rightwards double arrow  a + ( n - 1) d = 205
rightwards double arrow  7 + ( n - 1)6 = 205
rightwards double arrow  6(n - 1) = 205 - 7
rightwards double arrow  6(n - 1) = 198
rightwards double arrow space space space space space n minus 1 equals 198 over 6
rightwards double arrow    n - 1 = 33
rightwards double arrow    n = 33 + 1
rightwards double arrow    n = 34
Hence, the number of terms of the given A .P., is 34.