Find the number of terms in each of the following APs :
7, 13, 19, . . . , 205
7, 13, 19, . . . , 205
Here, a = 7
d = 13 - 7 = 6
And, an = 205
Let the number of terms be n.
Then, an = 205 a + ( n - 1) d = 205
7 + ( n - 1)6 = 205
6(n - 1) = 205 - 7
6(n - 1) = 198
n - 1 = 33
n = 33 + 1
n = 34
Hence, the number of terms of the given A .P., is 34.