Which term of the AP : 3, 8, 13, 18, . . . ,is 78?
The given A. P. is 3, 8, 13, 18, .....
Here, a = 3
d = 8 - 3 = 5
Let the nth term f=of the A. P. be 78
Then, an = a + (n - 1)d 78 = 3 + (n -1) (5)
5(n - 1) = 78 - 3
5 (n - 1) = 75
n - 1 = 15
n = 15 + 1
n = 16
Hence, 16th term of the A .P. is 78.