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Arithmetic Progressions

Question
CBSEENMA10007509
Wired Faculty App

In the following APs, find the missing terms in the boxes.

square comma space 13. space square. space 3



Solution

Let the first term and the common difference of the given A .P. be a and b respectively.
Second term = 13
⇒ a + (2 – 1) d = 13
⇒ a + d = 13 ...(i)
Fourth term = 3
⇒ a+ (4 – 1)d = 3
⇒ a + 3d = 3 ...(ii)
Solving (i) and (ii), we get
a = 18
d = –5
Therefore,
Third term = a + (3 – 1)d
= a + 2d
= 18 + 2(–5)
= 18 –10 = 8
Hence, the missing terms in the boxes are space space space space box enclose 18 space and space box enclose 8.

Some More Questions From Arithmetic Progressions Chapter

Write first four terms of the AP, when the first term a and the common difference d are given as follows:

a = – 1.25, d = – 0.25

For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .

For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .

For the following APs, write the first term and the common difference
0.6, 1.7, 2.8, 3.9, . . .

Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
– 1.2, – 3.2, – 5.2, – 7.2, . . .

Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
 –10, –6, –2, 2, ....

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